Question

Polygon ABCD is translated to create polygon A’B’C’D’. Point A is located at (1,5), and point A’ is located at (-2,1). What is the distance from B to B’?

Answer 1

The distance from B to B’ is
`5\ units`

Explanation:

we know that

In a translation the shape and dimensions of the figure are not going to change.

therefore

AA'=BB'=CC'=DD'

Find the distance AA'

the formula to calculate the distance between two points is equal to

`d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}`

`A(1,5)\\A'(-2.1)`

substitute the values

`AA'=\sqrt{(1-5)^(2)+(-2-1)^(2)}`

`AA'=\sqrt{(-4)^(2)+(-3)^(2)}`

`AA'=√(25)`

`AA'=5\ units`

therefore

`BB'=5\ units`