Question

The equation of a linear function in point-slope form is y - y1 = m(x - Xt). Harold correctly wrote the equation y = 3(x -

7) using a point and the slope. Which point did Harold use?
When Harold wrote his equation, the point he used was (7,3).
When Harold wrote his equation, the point he used was (0, 7).
When Harold wrote his equation, the point he used was (7,0).
When Harold wrote his equation, the point he used was (3, 7).

Answer 1

When Harold wrote his equation, the point he used was (7,0).

Explanation:

we know that

The equation of a line into point slope form is equal to

`y-y1=m(x-x1)`

where

(x1,y1) is the point

m is the slope

In this problem we have

`y=3(x-7)`

therefore

the point is (x1,y1)=(7,0)

the slope is m=3