Question

A fly has two alleles for the color of its eyes. the green allele is recessive and is represented by q. the blue allele is dominant and is represented by p. if 44 of 100 organisms are green, what is p?​

Answer 1

The answer would be C. 0.34

So
p+q=1(when u have 2 alleles)
0.44 of the population has recessive phenotype so is q^2.

q=radq^2=rad0.44=0.663

p=1-q=0.336=0.34

Answer 2

`p = 0.34`

Step-by-step explanation:

Given -

Green allele is recessive and is represented by "b"

Blue allele is dominant and is represented by "B"

Also out of
`100` organisms,
`44` are green in color. Thus, all these
`44` organism would have genotype "bb"

As per Hardy Weinberg's equation , frequency of "bb" is represented as
`q^(2)`

Thus frequency of allele "b" would be equal to

`\sqrt{q^(2) }`

`= \sqrt{(44)/(100) } \\= √(0.44) \\= 0.66`

As per first equation of Hardy Weinberg-

`p+q=1`

Frequency of allele "B" will be equal to

`p = 1-q`

Substituting the value of q, we get

`p = 1-0.66\\p = 0.34`