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A cylinder, with a piston pressing down with a constant pressure, is filled with 2.00 moles of a gas (n1), and its volume is 50.0 L (V1). If 0.400 mole of gas leak out, and the pressure and temperature remain the same, what is the final volume of the gas inside the cylinder?

asked
User Kuryaki
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7.9k points

1 Answer

3 votes

Answer:

40.0 L.

Step-by-step explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If P and T are constant, and have different values of n and V:

(V₁n₂) = (V₂n₁).

V₁ = 50.0 L, n₁ = 2.0 moles,

V₂ = ??? L, ​n₂ = 2.0 mol - 0.4 mol = 1.6 mol.

∴ V₂ = (V₁n₂)/(n₁) = (50.0 L)(1.6 mol)/(2.0 mol) = 40.0 L.

answered
User Jerry Bullard
by
7.8k points
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