Question

Does anyone know the answer to this question

Answer 1

`\cos B = ( √(3) )/(3)`

Step-by-step explanation

The given triangle is a right triangle.

It was given that,

`a = 1`

and

`b = √(2)`

Using the Pythagoras Theorem, we can determine the value of c.

`{c}^(2) = {( √(2) )}^(2) + {1}^(2)`

`{c}^(2) = 2 + 1`

`{c}^(2) = 3`

`c = √(3)`

The ratio is the adjacent over the hypotenuse.

`\cos B = (1 )/( √(3) )`

We rationalize to get:

`\cos B = ( √(3) )/( √(3) * √(3) ) = ( √(3) )/(3)`