Answer:
Required probability = 1/6
Explanation:
It is given that,
A red die is tossed the a green die is tossed
The possible outcomes of getting number greater than three when tossing red die are, 4, 5, and 6
The probability of tossing red die = 3/6
The possible outcomes of getting number less than three when tossing green die are 1 and 2
Probability of tossing green = 2/6
To find the required probability
Probability of getting red die shows greater than three and gree die shows less than three = (3/6)*(2/6) = 1/6