Question

Use the quadratic formula to solve the equation. 2x^2-6x+1=0 Enter your answers, in simplified radical form, in the boxes.

x=__or x=

please send me image and explain work

Answer 1

(3 (pm) sqrt(7))/2

Explanation:

First step: Identify a,b, and c

a=2

b=-6

c=1

Second step: Find b^2-4ac (this is called the discriminant-I will call this D)

(-6)^2-4(2)(1)=36-8=28

Third step: Find the square root of the discriminant aka sqrt(D)

sqrt(28)

Let's see if we can simplify sqrt(28)

Here is there a factor of 28 that is a perfect square? How about 4? Yep!

sqrt(28)=sqrt(4)sqrt(7)=2sqrt(7).

Fourth Step: What is -b? If b=-6 then -b=6.

Fifth step: What is 2a? 2(2)=4

So the formula is

x=(-b (pm) sqrt(D))/(2a)

or

x=(step4 (pm) step 3)/(step 5)

x=(6 (pm) 2sqrt(7))/4

Simplify

x=(3 (pm) sqrt(7))/2

*pm means plus or minus

*sqrt( ) means square root of the number that follows in the ( )

Answer 2

Just took it!

Explanation: