asked 11.5k views
3 votes
3. Mr. Terence had 18 boxes containing 36 donuts each. He sold 162 donuts and

repacked the rest into 81 boxes. How many donuts did he put into cach box?​

asked
User Pensu
by
8.2k points

1 Answer

3 votes

6 donuts. He repacked 6 donuts into each box .

Mr. Terence had 18 boxes containing 36 donuts each, that means:

Total donuts = n° boxes*n° donuts

Total donuts = 18*36 = 648

He had in total 648 donuts.

He sold 162 donuts and repacked the rest into 81 boxes. Then:

Rest donuts = Total donuts - sold donuts

Rest donuts = 648 - 162 = 486

The rest donuts are 486 donuts.

He repacked the rest into 81 boxes, then:

n° donuts (each box) = Rest donuts/n° boxes

n° donuts (each box) = 486/81 = 6

The number of donuts that he put in each box is 6 donuts.

answered
User HomerThinking
by
8.4k points
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