Question

A toy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. If acceleration due to gravity is –16 ft/s2, approximately how many seconds after the launch will the toy rocket reach the ground?

h(t) = at2 + vt + h0

Answer 1

it is in fact 3.80

Explanation:

I know the other person said that but I was just backing them up

Answer 2

it will take appr 3.8 seconds to hit the ground

Explanation:

h = -16t^2 + 60t + 3

at ground level , h = 0

16t^2 - 60t - 3 = 0

t = (60 ± √3792)/32

t = 3.799.. or t = a negative