asked 46.3k views
5 votes
Find 3 numbers in a geometrical sequence if:

a1+a2+a3=21
a1xa2xa3=64 (That x is multiplying)

1 Answer

2 votes

a1+a2+a3=21

(a1=1,a2=3,a3=7)

a1xa2xa3=64

(a1=2,a2=4,a3=8)

answered
User Hsiao
by
8.2k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.