Question

-2x^2-6x-8=0 what is the solution using the quadratic equation

Answer 1

x=-4, x=1

Explanation:

`x=\frac{-(-6)+\sqrt{(-6)^(2)-4(-2) 8 } }{2(-2)} : -4\\x=\frac{-(-6)-\sqrt{(-6)^(2) -4(-2) 8} }{2(-2)} : 1\\`