Question

A rectangle is 8m longer than it is wide. Its perimeter is 56m. Find its length and width.

Write values only.

Answer 1

The length is
`18\ m` and the width is
`10\ m`

Explanation:

Let

x -----> the length of the rectangle

y -----> the width of the rectangle

we know that

The perimeter of rectangle is equal to

`P=2(x+y)`

`P=56\ m`

so

`56=2(x+y)`

`28=(x+y)` ------> equation A

`x=y+8` -----> equation B

Substitute equation B in equation A and solve for y

`28=(y+8+y)`

`28=2y+8`

`2y=20`

`y=10\ m`

Find the value of x

`x=10+8=18\ m`

therefore

The length is
`18\ m` and the width is
`10\ m`