Question

A train moves moves from rest to a speed of 25 m/s in 30.0 sec . what is its acceleration

Answer 1

a = Delta v/Delta t
Delta v = 25 - 0 = 25
Delta t = 30
25/30 = 5/6 = 1.66 repeating

Answer 2

Acceleration = (change in speed) / (time for the change)

Change in speed = 25 m/s

Time for the change = 30 sec

Acceleration = (25 m/s) / (30 sec)

Acceleration = (25/30) (m/s /s)

Acceleration = 0.833... m/s²