Question

The equation of the circle whose center is at (2, 1) and radius is 3 is

Answer 1

The equation for that circle would be: (x - 2)^2 + (y - 1)^2 = 9

Answer 2

Answer: The equation of the circle whose center is at (2, 1) and radius is 3 is
`(x-2)^2+(y-1)^2=9`

Explanation:

We know that the equation of a circle having center at (h,k) and radius r is given by :-

`(x-h)^2+(y-k)^2=r^2`

Given : The center of the circle : (2, 1)

The radius of the circle : 3 units

Then the equation of a circle with center at (2, 1) and radius is 3 is will be :-

`(x-2)^2+(y-1)^2=3^2\\\\\Rightarrow\ (x-2)^2+(y-1)^2=9`