How do I break up (x^2 -4x+8) into like (x blabla)(x blabla)

Question

asked Apr 4, 2020 206k views

2 Answers

Adrian Cox · Answer 1 · 2020-04-09T19:48:30+0000

Answer:

You can't break it in the form of (x blabla)(x blabla) since there are no real roots.

Explanation:

Proof:

x^2 - 4x + 8 = 0

(x - 2)^2 = - 4

x=2 + 2i or x= 2 - 2i (Complex numbers)