Question

if f(x)=2(x)^2+5sqrt(x+2), complete the follwoing statement ( round your answer to the nearest hundreth) : f(0)=_____

Answer 1

`f(0)=7.07`

Explanation:

We have the function
`f(x)=2(x)^2+5√((x+2))`

In this case we want to find the value of f0)

To find f(0) you must replace the x in the function with the number 0 and solve as shown below

`f(0)=2(0)^2+5√((0+2))`

`f(0)=0+5√((0+2))`

`f(0)=5√((2))`

Therefore

`f(0)=7.07`