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What is the product of d – 9 and 2d2 + 11d – 4?

2 Answers

6 votes
The answer to your question is 2d^3-7d^2-103d+36
answered
User Mauro Sala
by
8.4k points
4 votes

Answer:


2d^3-7d^2-103d+36

Explanation:

The given expressions are (d-9) and
2d^2+11d-4.

Their product is given by:


(d-9)(2d^2+11d-4)

We expand using the distributive property to obtain;


d(2d^2+11d-4)-9(2d^2+11d-4)


2d^3+11d^2-4d-18d^2-99d+36

We group similar terms to get;


2d^3+11d^2-18d^2-4d-99d+36

We combine the similar terms to get:


2d^3-7d^2-103d+36

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