Question

100 ml of gaseous hydrocarbon consumes 300

ml of oxygen for the complete combustion.
The hydrocarbon is

a. C2H4
b. C2H2
C. C3H8
d. C2H6​

Answer 1

a. C2H4.

Step-by-step explanation:

Let's look at the balanced equation for C2H4.

C2H4 + 3O2 --> 2CO2 + 2H2O

So 1 mole of this hydrocarbon reacts with 3 moles of oxygen and since 1 mole of one gas occupies the same volume as another gas, the volumes will be in the ratio 1:3. So this is the required hydrocarbon.

Answer 2

The answer would be a. C2H4(ethylene)

1C2H4+3O2~>2CO2+2H2O