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Angle θ is in standard position. If (8, -15) is on the terminal ray of angle θ, find the values of the trigonometric functions.

asked
User BJury
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7.6k points

2 Answers

0 votes

Answer:

sin=-15/17

cos=8/7

tan=-15/8

csc=-17/15

sec=17/8

cot=-8/15

answered
User Friction
by
9.2k points
3 votes

ANSWER


\sin( \theta) = - (15)/(17)


\csc( \theta) = - (17)/(15)


\cos( \theta) = (8)/(17)


\sec( \theta) = (17)/(8)


\tan( \theta) = - (15)/(8)


\cot( \theta) = - (8)/(15)

Step-by-step explanation

From the Pythagoras Theorem, the hypotenuse can be found.


{h}^(2) = 1 {5}^(2) + {8}^(2)


{h}^(2) = 289


h = √(289)


h = 17

The sine ratio is negative in the fourth quadrant.


\sin( \theta) = - (opposite)/(hypotenuse)


\sin( \theta) = - (15)/(17)

The cosecant ratio is the reciprocal of the sine ratio.


\csc( \theta) = - (17)/(15)

The cosine ratio is positive in the fourth quadrant.


\cos( \theta) = (adjacent)/(hypotenuse)


\cos( \theta) = (8)/(17)

The secant ratio is the reciprocal of the cosine ratio.


\sec( \theta) = (17)/(8)

The tangent ratio is negative in the fourth quadrant.


\tan( \theta) = - (opposite)/(adjacent)


\tan( \theta) = - (15)/(8)

The reciprocal of the tangent ratio is the cotangent ratio


\cot( \theta) = - (8)/(15)

Angle θ is in standard position. If (8, -15) is on the terminal ray of angle θ, find-example-1
answered
User Eric Hauenstein
by
8.2k points

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