asked 141k views
3 votes
Factorise completely 9a^2-1

asked
User Gissel
by
7.6k points

1 Answer

3 votes

Answer:

(3a-1)(3a+1)

Explanation:

This is the difference of two squares so we can factorise using the rules

x^2-y^2 = (x-y)(x+y)

In this case x = 3a and y = 1 since (3a)^2 = 9a^2 and 1^2 = 1

answered
User Zalew
by
8.6k points

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