asked 123k views
3 votes
Find the sum of the first 100
terms of the arithmetic
sequence
a1=15 and a 100=307

1 Answer

6 votes

Answer:

16100

Explanation:

n = 100

a1 = 15

a100 = 307

The first thing you have to do is solve for d

a100 = a1 + (n - 1)*d

307 = 15 + (100 - 1)*d

307 = 15 + 99*d

307 - 15 = 99*d

292 = 99 d

d = 292 / 99

d = 2.94949494

That's a real odd result, but it is what you get.

Sum = (a + L)*n/2

sum = (15 + 307)*n/2

Sum = 322 * 100 / 2

Sum = 16100 It looks like I didn't have to solve for d. The person who made this up sure didn't

answered
User JerryM
by
8.5k points

Related questions

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.