Register

What are the roots of f(x) = x2 - 48? -48 and 48 -24 and 24 -8/5 and 83 -4,3 and 43

What are the roots of f(x) = x2 - 48? -48 and 48 -24 and 24 -8/5 and 83 -4,3 and 43
asked 98.0k views
4 votes
What are the roots of f(x) = x2 - 48?

-48 and 48
-24 and 24
-8/5 and 83
-4,3 and 43

asked
User Taran
by
7.8k points

2 Answers

3 votes

Answer:

It is D

Explanation:

I just took the test

answered
User Jeffrey Chen
by
8.0k points
3 votes
Answer: 4sqrt(3), -4sqrt(3)

x^2-48=0
x^2=48
x=+/-sqrt(48)=4sqrt(3),-4sqrt(3)
answered
User Rory Solley
by
8.1k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!