Question

How much heat is absorbed by 15.5g of steam to turn into liquid water when its temperature is decreased from 120.0°C to 100.0°C?

Answer 1

- 618.8 J.

Step-by-step explanation:

• To solve this problem, we can use the relation:

Q = m.c.ΔT,

where, Q is the amount of heat released by steam (Q = ??? J).

m is the mass of the steam (m = 15.5 g).

c is the specific heat of the steam (c of steam = 1.996 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 100.0°C - 120.0°C = - 20.0°C).

∴ Q = m.c.ΔT = (15.5 g)(1.996 J/g.°C)(- 20.0°C) = - 618.8 J.