Please help i don't have alot time

Question

asked May 20, 2020 71.3k views

1 Answer

Tania · Answer 1 · 2020-05-26T04:11:58+0000

Answer:

$g\left(x\right)=-√(x+3)+8$

Explanation:

Given function is
$f\left(x\right)=-2√(x-3)+8$ .

Now let's find it's range.

we know that square root function always gives positive output then:

$√(x-3)\ge0$

$-2√(x-3)\le-2\left(0\right)$

$-2√(x-3)\le0$

$-2√(x-3)+8\le0+8$

$-2√(x-3)+8\le 8$

$f(x) \le 8$

Hence range of the function is
$(-\infty,8]$ .

we can repeat same process to find the range of all the given choices.

we will find that only 3rd choice has same range.

Hence final answer is
$g\left(x\right)=-√(x+3)+8$