Question

Please help ASAP!!!!​

Answer 1

A.
`x=6` or
`x=1`

Explanation:

The given function is:

`y=x^2-7x+6`

When y=0; we have:

`x^2-7x+6=0`

`x^2-6x-x+6=0`

Factor by grouping:

`x(x-6)-1(x-6)=0`

`(x-6)(x-1)=0`

Either
`(x-6)=0` or
`(x-1)=0`

Either
`x=6` or
`x=1`