Question

The density of Maplewood is 39 pounds per cubic foot. If a cylindrical maple tree stump is 3 feet high and has a radius of 1.5 feet, what is the weight of the stump to the nearest pound? Use 3.14 for pi, and enter the number only.

Answer 1

Answer: 827 pounds.

Explanation:

The formula for calculate density is:

`d=(m)/(V)`

Where "m" is the mass and "V" is the volume.

The formula for calculate the volume of a cylinder is:

`V=\pi r^2h`

Where "r" is the radius and "h" is the height.

Calculate the volume of the cylindrical maple tree stump, which is 3 feet high and has a radius of 1.5 feet:

`V=(3.14)(1.5ft)^2(3ft)=21.195ft^3`

Substitute the volume into and the density 39 pounds per cubic foot, into the formula
`d=(m)/(V)` and solve for "m". Then, the weight of the stump to the nearest pound is:

`39(lb)/(ft^3)=(m)/(21.195ft^3)\\\\m=(39(lb)/(ft^3))(21.195ft^3)\\\\m=827lb`