Question

Misha wrote the quadratic equation 0=-x2+4x-7 in standard form. what is the value of c in her equation

Answer 1

Final answer is c=-7.

Explanation:

Given equation is
`0=-x^2+4x-7`.

Now question says that Misha wrote the quadratic equation 0=-x2+4x-7 in standard form. Now we need to find about what is the value of c in her equation.

We know that standard form of quadratic equation is given by
`ax^2+bx+c=0`.

compare given equation with the standard form, we find that -7 is written in place of +c

so that means +c=-7

or c=-7

Hence final answer is c=-7.