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3 votes
Evaluate 5!/3! HELP ME PLEASE

2 Answers

5 votes

For this case we have that by definition, the factorial of a number is the product of the "n" consvutive factors from n to 1. The factors are in descending order, that is:


n! = n (n-1) (n-2) ... 3 * 2 * 1

Then, we have the following expression:


\frac {5!} {3!}

Applying the definition we have:


\frac {5!} {3!} = \frac {5 * 4 * 3 * 2 * 1} {3 * 2 * 1} = \frac {120} {6} = 20

ANswer:

20

answered
User Max Sherbakov
by
8.5k points
1 vote

Answer:

20

Explanation:

5! = 5*4*3*2*1

3! = 3*2*1

5!/3! = 5*4*3*2*1

----------------

3*2*1

Canceling common factors

= 5*4

= 20

answered
User Ocespedes
by
8.6k points

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