Question

Suppose the volume of a cylinder is 169.65 ft cubes and the height is twice the radius what is the radius of the cylinder.

Answer 1

The radius of the cylinder is
`r=3\ ft`

Explanation:

we know that

The volume of the cylinder is equal to

`V=\pi r^(2) h`

we have

`V=169.65\ ft^(3)`

`h=2r\ ft`

assume

`\pi=3.14`

substitute the values and solve for r

`169.65=(3.14)r^(2) (2r)`

`169.65=(6.28)r^(3)`

`r^(3)=169.65/(6.28)`

`r=3\ ft`