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5 votes
What are the first four terms of 3n²

2 Answers

5 votes

Answer:

3;14;27;48

Explanation:

answered
User Pieter Ennes
by
8.5k points
6 votes

Answer:

3, 12, 27, 48

Explanation:

To find the first 4 terms substitute n = 1, 2, 3, 4 into the rule, that is

n = 1 → 3 × 1² = 3 × 1 = 3 ← first term

n = 2 → 3 × 2² = 3 × 4 = 12 ← second term

n = 3 → 3 × 3² = 3 × 9 = 27 ← third term

n = 4 → 3 × 4² = 3 × 16 = 48 ← fourth term

answered
User Dino Tw
by
7.7k points

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