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Find the product of -7-i and its complex conjugate

asked
User Dulgan
by
8.0k points

1 Answer

4 votes

Answer:

50

Explanation:


-7-i\\\\\text{complex conjugate:}\ -7+i\\\\(-7-i)(-7+i)\qquad\text{use}\ (a+b)(a-b)=a^2-b^2\\\\=(-7)^2-(i)^2\qquad\ i=√(-1)\to i^2=-1\\\\=49-(-1)\\\\=49+1\\\\=50

answered
User Sanoodia
by
7.9k points

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