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Given f(x)=x^2 and g(x)=x-6 find values of x for which g(x)=0

1 Answer

12 votes

Answer:

5

Explanation:

Remark

Start with the meaning of g[f(x)]. This when you write g(x), where ever you see and x in g(x), put in an f(x)

g(f(x))

g(x)= x + 1 Substitute f(x) for x

g(f(x)) = f(x) + 1 Substitute x^2 for f(x)

g(f(x)) = x^2 + 1

g(f(-2)) = (-2)^2 + 1 Substitute -2 for x

g(f(-2)) = (4) + 1

g(f(-2)) = 5

answered
User Nick Olsen
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