Question

Three consecutive integers have a sum of 246. what are the three integers?​

Answer 1

81,82 and 83

Explanation:

X + X + 1 + X + 2 = 246

3X + 3 = 246

3X + 3 - 3 = 246 - 3

3X = 243

3X/3 = 243/3

X = 81

Which means that the first number is 81, the second number is 81 + 1 and the third number is 81 + 2. Therefore, three consecutive integers that add up to 246 are 81, 82, and 83.

81 + 82 + 83 = 246