Question

What values of b satisfy 3(2b + 3)^2 = 36?

Answer 1

3(2b+3)^2=36

(2b+3)^2=12

2b+3=+2 radical3

2b+3= 2 radical 3

b=- radical 3 -3 over 2

b= radical 3- 3 over 2

b=- radical 3 - 3 over 2

Answer 2

The answer is A

Explanation: