Question

Identify a and b in the binomial expression (2x3 + 3y2)7.​

Answer 1

`a=2x^3` and
`b=3y^2`

Explanation:

The given binomial expression is:
`(2x^3+3y^2)^7`

A standard binomial expression is like
`(a+b)^n`

Comparing the given expression with the standard binomial expression.....

`(a\ \ +\ \ b)^n \Longleftrightarrow (2x^3\ +\ 3y^2)^7\\ \\ So,\ \ a=2x^3\\ \\ and\ \ b=3y^2`

Answer 2

`\text{Hey there!}`

`\text{Distribute the value of 7 in each of your terms}`

`\text{(2x}^3+\text{3y}^2)(7)`

`\text{2x}^3*7=\text{14x}^3`

`\text{3y}^2*7=\text{21y}^2`

`\text{We cannot combine like terms because they AREN'T any in this equation}`

`\boxed{\boxed{\bf{Answer:14x^3+21y^2}}}\checkmark`

`\text{Good luck on your assignment and enjoy your day!}`

~
`\frak{LoveYourselfFirst:)}`