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Please help I've failed this many times

Please help I've failed this many times-example-1
asked
User Sanghoon
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1 Answer

4 votes

Answer:

  • x-intercept (9, 0)
  • y-intercept (0, 17.5)

Explanation:

You can compute the slope from two of the points, then write the point-slope form of the equation of the line.

slope = (change in y)/(change in x)

= (15 -20)/(3 -1) = -5/2

Then the equation of the line, using the first point) is ...

y = m(x -h) +k . . . . . . for slope m through point (h, k)

y = -5/2(x -1) +20

The x-intercept is the value of x where y=0:

0 = -5/2(x -1) +20 . . .put 0 where y is in the equation, then solve for x

0 = (x -1) -8 . . . . . . . . multiply by -2/5 (the inverse of the x-coefficient)

9 = x . . . . . . . . . . . . . simplify, add 9

The x-intercept is (9, 0).

__

The y-intercept is the value of y where x=0:

y = -5/2(0 -1) +20 . . . . . . put 0 where x is in the equation, then solve for y.

y = -2.5 +20 = 17.5

The y-intercept is (0, 17.5).

_____

Comment on the problem

Your question page seems to offer both lesson and video help. Either or both may be better than the written solution here.

answered
User Stasiaks
by
8.3k points

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