Question

Find the product of the expression:
(3x^2) (5x^8) (6x^5)

Answer 1

`\left(3x^2\right)\left(5x^8\right)\left(6x^5\right)=90x^(15)`

Explanation:

Given the expression

`\left(3x^2\right)\left(5x^8\right)\left(6x^5\right)`

Apply the exponent rule:

`a^b\cdot \:a^c=a^(b+c)`

so the expression becomes

`\left(3x^2\right)\:\left(5x^8\right)\:\left(6x^5\right)=3\cdot \:\:5\cdot \:\:6x^(2+8+5)`

Add the exponent numbers: 2+8+5=15

`=3\cdot \:5\cdot \:6x^(15)`

Multiply the numbers: 3×5×6=90

`=90x^(15)`

Therefore, we conclude that:

`\left(3x^2\right)\left(5x^8\right)\left(6x^5\right)=90x^(15)`