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7x^2/2x+6 divided by 3x-5/x+3

asked
User Senneco
by
7.6k points

1 Answer

4 votes

Answer:


\large\boxed{(7x^2)/(6x-10)}

Explanation:


(7x^2)/(2x+6)/(3x-5)/(x+3)=(7x^2)/(2(x+3))\cdot(x+3)/(3x-5)\\\\\text{cancel}\ (x+3)\\\\=(7x^2)/(2)\cdot(1)/(3x-5)=((7x^2)(1))/((2)(3x-5))\\\\\text{use the distributive property}\ a(b-c)=ab-ac\\\\=(7x^2)/(6x-10)

answered
User Ewooycom
by
8.4k points

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