Question

Rationalize the denominator and simplify. StartFraction 5 minus StartRoot 3 EndRoot Over 4 plus 2 StartRoot 3 EndRoot EndFraction

Answer 1

0.25

Explanation:

Answer 2

`(13-7√(3))/(2)`

Explanation:

We need to rationalize the denominator of
`= (5-√(3))/(4+2√(3))`. For rationalizing we multiply the equation by
`(4-2√(3))/(4-2√(3))`

So, solving

`= (5-√(3))/(4+2√(3))*(4-2√(3))/(4-2√(3)) \\=((5-√(3))(4-2√(3)))/(4+2√(3)*4-2√(3))\\=((5-√(3))(4-2√(3)))/((4)^2-(2√(3))^2)\\= (5(4-2√(3))-√(3)(4-2√(3)))/(16-(4*3))\\=(20-10√(3)-4√(3)+2*3)/(16-12)\\=(20+6-14√(3))/(4)\\=(26-14√(3))/(4)\\= (2(13-7√(3)))/(4)\\=(13-7√(3))/(2)`