Question

A set of 36 cards is numbered with the positive integers from 1 to 36. If the cards are shuffled and one is chosen at random, what is the probability that the number on the card is a multiple of both 4 and 6?

Answer 1

1/12.

Explanation:

The numbers divisible by 6 are 6, 12, 18, 24, 30 and 36.

Of these 12, 24 and 36 are also divisible by 4.

So the required probability is 3/36

= 1/12.