Question

Tx^2+3x-7=0 has two real solutions. What can be deduced from value of T?

Answer 1

T > -9/28

Explanation:

A quadratic has two real solutions when the discriminant (b² - 4ac) is positive.

b² - 4ac > 0

3² - 4(T)(-7) > 0

9 + 28T > 0

28T > -9

T > -9/28