Question

TIMED!!!

Marlon built a ramp to put in front of the curb near his driveway so he could get to the sidewalk more easily from the street on his bike.

If the ramp includes the flat piece as well as the angled piece and is made entirely out of concrete, what is the total amount of concrete in the ramp?
768in^3
936in^3
984in^3
1,080in^3

Answer 1

The guy above me is correct lol

Explanation:

Answer 2

Answer: Last option.

Explanation:

The total amount of concrete in the ramp (
`V_t`) will be the sum of the volume of the rectangular prism (
`V_(rp)`) and the volume of the triangular prism (
`V_(tp)`)

`V_t=V_(rp)+V_(tp)`

The formulas are:

`V_(rp)=lwh`

Where "l" is the lenght, "w" is the width and "h" is the height.

`V_(tp)=(bhl)/(2)`

Where "l" is the lenght, "b" is the base and "h" is the height.

Substituting, we get:

`V_t=V_(rp)+V_(tp)\\\\V_t=lwh+(bhl)/(2)\\\\V_t=(18in)(6in)(6in)+((8in)(6in)(18in))/(2)\\\\V_t=1,080in^3`