The vector [ 5,1] represent the velocity of an ultralight plane what is the direction of this vector to the nearest degree

Question

asked Oct 2, 2020 127k views

1 Answer

Anurag · Answer 1 · 2020-10-09T10:33:03+0000

Answer:

$011\degree$

Explanation:

The direction of a vector is given by;

$\theta=\tan^(-1)((y)/(x))$

The given vector is <5,1>.

The x-component of this vector is 5 and the y-component is 1.

We substitute the values into the formula to obtain;

$\theta=\tan^(-1)((1)/(5))$

We use our scientific calculator to obtain;

$\theta=11.3099$

Therefore the direction of the given angle is
$011\degree$ to the nearest degree.