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What is the exponential form of 3*3*3*3*x*x*x*z*z?

2 Answers

3 votes

Answer:

9xz√x

Explanation:

you take two 3's you pair them up you do the two time witch gives you three times three or nine you then pair up the x's giving you 9x and that leaves one x to go on the inside of the sq root symbol then you pair up the z's and because there are only two z's put them together on the outside equaling 9xz√x

answered
User Aaron Franke
by
9.3k points
3 votes

3*3*3*3 = 3^4 = 81

x*x*x = x^3

z*z = z^2

3*3*3*3*x*x*x*z*z =

3^4x^3z^2 =

81x^3z^2

answered
User Eydrian
by
8.1k points

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