Question

Calculate the pH of a solution with [OH−]=1.3×10−2M. (Hint: Begin by using Kw to find [H3O+].)

Answer 1

12.11.

Step-by-step explanation:

∵ pOH = - log[OH⁻]

∴ pOH = - log(1.3 x 10⁻²) = 1.886.

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 1.886 = 12.11.