asked 58.1k views
3 votes
If <ACD <BCD which of the following relationships can be proved and
why?


If <ACD <BCD which of the following relationships can be proved and why? ​-example-1
asked
User Amro
by
8.0k points

2 Answers

5 votes

Answer:C

Explanation:

answered
User Daniel Becker
by
7.8k points
3 votes

Answer:

Option C.

Explanation:

we know that

The Angle-Side-Angle (ASA) postulate states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent.

In this problem

The included side is the side CD and the angle ∠ACD and ∠ADC of triangle ACD are congruent with angle ∠BCD and ∠CDB of triangle BCD

therefore

Triangles ACD and BCD are congruent by ASA

answered
User Igor Zilberman
by
9.1k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.