Question

Plz help me with this

Answer 1

The answer is B. Since there are no parenthesis around pi/2, it stating that the graph shifts up pi/2 units - which is incorrect. It is a phase shift of pi/2 units (not a vertical shift).

Answer 2

Answer:
`\bold{B)\quad y=2\ sin2x+(\pi)/(2)}`

Explanation:

`\text{The standard form of a sine equation is: y=A sin(Bx - C) + D}\\\\\bullet\text{A = amplitude}\\\\\bullet\text{Period = }(2\pi)/(B)\\\\\bullet\text{Phase Shift = }(C)/(B)\\\\\bullet\text{D = vertical shift (up if positive, down if negative)}`

In the given graph,

• A (amplitude) = 2
• Phase Shift
  `\bigg((C)/(B)\bigg)` =
  `(\pi)/(2)` to the left
• P (period) = π --> B = 2

• D (vertical shift) = 0

Option B shows the value of D as
`(\pi)/(2)`, which is incorrect since there is no vertical shift up. If the parenthesis included that value, like Option C, then it would have been correct.