Question

Compute the resistance in ohms of a lead block 10 cm long and .10 cm^2 in a cross sectional area (p=2.2 x 10^-5 ohm-cm

Answer 1

`2.2\cdot 10^(-3) \Omega`

Step-by-step explanation:

The resistance of the lead block is given by

`R=(\rho L)/(A)`

where

`\rho = 2.2\cdot 10^(-5)\Omega cm` is the resistivity of lead

`L = 10 cm` is the length of the block

`A=0.10 cm^2` is the cross sectional area of the block

Substituting into the equation, we find

`R=((2.2\cdot 10^(-5) \Omega cm)(10 cm))/(0.10 cm^2)=2.2\cdot 10^(-3) \Omega`