Question

Write the equation in exponential form. Log 4 1/16 =-2

Answer 1

see explanation

Explanation:

Using the rule of logarithms

•
`log_(b)` x = n ⇔ x =
`b^(n)`

Hence

with b = 4 and n = - 2

`log_(4)`
`(1)/(16)` = - 2, then

`(1)/(16)` =
`4^(-2)` ← in exponential form

Answer 2

The exponential form is

`(1)/(16) = {4}^( - 2)`

EXPLANATION

The given logarithm is

`log_(4)( (1)/(16) ) = - 2`

We want to write the given logarithm in exponential form:

We take the antilogarithm of both sides to obtain:

`{4}^{log_(4)( (1)/(16) )} = {4}^( - 2)`

We simplify the left hand side to obtain:

`(1)/(16) = {4}^( - 2)`

Hence the exponential form is

`(1)/(16) = {4}^( - 2)`