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Which expression is equivalent to (4 sqrt of 6)/(cube root of 2)?

a - (12 sqrt of 27)/2
b - (4 sqrt of 24)/2
c- (12 sqrt of 55296)/2
(12 sqrt of 177147)/3

asked
User Mtuulu
by
8.3k points

2 Answers

3 votes

Answer:

A!!!!

12^sqrt 27/ 2

Explanation:

answered
User Artyomska
by
8.3k points
4 votes

For this case we must find an expression equivalent to:


\frac{4√(6)}{\sqrt[3]{2}}

We multiply by:


(\frac{(\sqrt[3]{2})^2}{(\sqrt[3]{2})^2})\\\frac{4√(6)}{\sqrt[3]{2}}*(\frac{(\sqrt[3]{2})^2}{(\sqrt[3]{2})^2})=

By definition of multiplication of powers of the same base we have:


a^n*a^m=a^(m+n)\\\frac{4√(6)*(\sqrt[3]{2})^2}{(\sqrt[3]{2})^3}=\\\frac{4√(6)*(\sqrt[3]{2})^2}{2}=

Move the exponent within the radical:


\frac{4√(6)*\sqrt[3]{2^2}}{2}=\\\frac{4√(6)*\sqrt[3]{4}}{2}=

We rewrite:


4^{(1)/(3)}=4^{(2)/(6)}=\sqrt[6]{4^2}\\6^{(1)/(2)}=6^{(3)/(6)}=\sqrt[6]{6^3}

Rewriting the expression:


\frac{4\sqrt[6]{4^2}\sqrt[6]{6^3}}{2}=\\\frac{4\sqrt[6]{16*216}}{2}=\\\frac{4\sqrt[6]{3456}}{2}=\\\frac{4\sqrt[6]{2^6*54}}{2}=\\\frac{8\sqrt[6]{54}}{2}=\\4\sqrt[6]{54}

Answer:


4\sqrt[6]{54}

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